epsFloating point relative accuracy
eps1.0 to the next larger double-precision number.eps(A)abs(A) to the next larger double-precisoin number.A should be a numeric array.A.eps(inf) and eps(nan) return nan.eps gives a constant value of 2^-52.eps == 2^-52
ans =
1
a = rand(2,3)-0.5
eps(a)
a = 1e-1 ×
-0.577 -4.369 -1.600
0.894 -0.660 -0.880
ans = 1e-17 ×
0.694 5.551 2.776
1.388 1.388 1.388